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102020132223133 is a prime number
BaseRepresentation
bin10111001100100101101001…
…101111011011100010011101
3111101020000210102111021112121
4113030211221233123202131
5101332444212322120013
61000551222435102541
730326465660544355
oct2714455157334235
9441200712437477
10102020132223133
112a563549a871a3
12b538227a41a51
1344c05c359b587
141b29b2d365b65
15bbdb9ee3558d
hex5cc969bdb89d

102020132223133 has 2 divisors, whose sum is σ = 102020132223134. Its totient is φ = 102020132223132.

The previous prime is 102020132223083. The next prime is 102020132223151. The reversal of 102020132223133 is 331322231020201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92592640965049 + 9427491258084 = 9622507^2 + 3070422^2 .

It is a cyclic number.

It is not a de Polignac number, because 102020132223133 - 29 = 102020132222621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102020132223098 and 102020132223107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102020132223833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51010066111566 + 51010066111567.

It is an arithmetic number, because the mean of its divisors is an integer number (51010066111567).

Almost surely, 2102020132223133 is an apocalyptic number.

It is an amenable number.

102020132223133 is a deficient number, since it is larger than the sum of its proper divisors (1).

102020132223133 is an equidigital number, since it uses as much as digits as its factorization.

102020132223133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 102020132223133 its reverse (331322231020201), we get a palindrome (433342363243334).

The spelling of 102020132223133 in words is "one hundred two trillion, twenty billion, one hundred thirty-two million, two hundred twenty-three thousand, one hundred thirty-three".