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10202202013 is a prime number
BaseRepresentation
bin10011000000001100…
…10011111110011101
3222100000020120010211
421200012103332131
5131343230431023
64404204332421
7510551200123
oct114006237635
928300216124
1010202202013
114365971413
121b88844111
13c67865b33
146cad59913
153ea9eea0d
hex260193f9d

10202202013 has 2 divisors, whose sum is σ = 10202202014. Its totient is φ = 10202202012.

The previous prime is 10202202011. The next prime is 10202202029. The reversal of 10202202013 is 31020220201.

10202202013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8420264644 + 1781937369 = 91762^2 + 42213^2 .

It is an emirp because it is prime and its reverse (31020220201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10202202013 - 21 = 10202202011 is a prime.

It is a super-2 number, since 2×102022020132 (a number of 21 digits) contains 22 as substring.

Together with 10202202011, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10202201984 and 10202202002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10202202011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5101101006 + 5101101007.

It is an arithmetic number, because the mean of its divisors is an integer number (5101101007).

Almost surely, 210202202013 is an apocalyptic number.

It is an amenable number.

10202202013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10202202013 is an equidigital number, since it uses as much as digits as its factorization.

10202202013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 10202202013 its reverse (31020220201), we get a palindrome (41222422214).

It can be divided in two parts, 1020220201 and 3, that multiplied together give a palindrome (3060660603).

The spelling of 10202202013 in words is "ten billion, two hundred two million, two hundred two thousand, thirteen".