Base | Representation |
---|---|
bin | 10011000001001000… |
… | …00110111110111001 |
3 | 222100112221101221211 |
4 | 21200210012332321 |
5 | 131402230404423 |
6 | 4405044003121 |
7 | 511004452036 |
oct | 114044067671 |
9 | 28315841854 |
10 | 10210013113 |
11 | 436a316a73 |
12 | 1b8b3904a1 |
13 | c6936c2a1 |
14 | 6cbdd038d |
15 | 3eb54410d |
hex | 260906fb9 |
10210013113 has 2 divisors, whose sum is σ = 10210013114. Its totient is φ = 10210013112.
The previous prime is 10210013111. The next prime is 10210013117. The reversal of 10210013113 is 31131001201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6699095104 + 3510918009 = 81848^2 + 59253^2 .
It is a cyclic number.
It is not a de Polignac number, because 10210013113 - 21 = 10210013111 is a prime.
Together with 10210013111, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 10210013093 and 10210013102.
It is not a weakly prime, because it can be changed into another prime (10210013111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105006556 + 5105006557.
It is an arithmetic number, because the mean of its divisors is an integer number (5105006557).
Almost surely, 210210013113 is an apocalyptic number.
It is an amenable number.
10210013113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10210013113 is an equidigital number, since it uses as much as digits as its factorization.
10210013113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 10210013113 its reverse (31131001201), we get a palindrome (41341014314).
The spelling of 10210013113 in words is "ten billion, two hundred ten million, thirteen thousand, one hundred thirteen".
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