10210013111 has 2 divisors, whose sum is σ = 10210013112. Its totient is φ = 10210013110.

The previous prime is 10210013059. The next prime is 10210013113. The reversal of 10210013111 is 11131001201.

It is a happy number.

10210013111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11131001201) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10210013111 is a prime.

Together with 10210013113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10210013092 and 10210013101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10210013113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105006555 + 5105006556.

It is an arithmetic number, because the mean of its divisors is an integer number (5105006556).

Almost surely, 2^10210013111 is an apocalyptic number.

10210013111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10210013111 is an equidigital number, since it uses as much as digits as its factorization.

10210013111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 10210013111 its reverse (11131001201), we get a palindrome (21341014312).

The spelling of 10210013111 in words is "ten billion, two hundred ten million, thirteen thousand, one hundred eleven".