Search a number
-
+
102112130053 is a prime number
BaseRepresentation
bin101111100011001011…
…0110111010000000101
3100202120100222122222201
41133012112313100011
53133111201130203
6114524253154501
710243301533033
oct1370626672005
9322510878881
10102112130053
113a33a6a972a
121795918ba31
13982428683b
144d29787553
1529c989ae1d
hex17c65b7405

102112130053 has 2 divisors, whose sum is σ = 102112130054. Its totient is φ = 102112130052.

The previous prime is 102112130051. The next prime is 102112130077. The reversal of 102112130053 is 350031211201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 64271376324 + 37840753729 = 253518^2 + 194527^2 .

It is a cyclic number.

It is not a de Polignac number, because 102112130053 - 21 = 102112130051 is a prime.

Together with 102112130051, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 102112130053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102112130051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056065026 + 51056065027.

It is an arithmetic number, because the mean of its divisors is an integer number (51056065027).

Almost surely, 2102112130053 is an apocalyptic number.

It is an amenable number.

102112130053 is a deficient number, since it is larger than the sum of its proper divisors (1).

102112130053 is an equidigital number, since it uses as much as digits as its factorization.

102112130053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 102112130053 its reverse (350031211201), we get a palindrome (452143341254).

The spelling of 102112130053 in words is "one hundred two billion, one hundred twelve million, one hundred thirty thousand, fifty-three".