Base | Representation |
---|---|
bin | 10011000001011000… |
… | …01001011001001111 |
3 | 222100200220110020222 |
4 | 21200230021121033 |
5 | 131403300321033 |
6 | 4405201101555 |
7 | 511031406011 |
oct | 114054113117 |
9 | 28320813228 |
10 | 10212120143 |
11 | 4370526015 |
12 | 1b900278bb |
13 | c69929354 |
14 | 6cc3bc1b1 |
15 | 3eb80d598 |
hex | 260b0964f |
10212120143 has 2 divisors, whose sum is σ = 10212120144. Its totient is φ = 10212120142.
The previous prime is 10212120077. The next prime is 10212120157. The reversal of 10212120143 is 34102121201.
It is a strong prime.
It is an emirp because it is prime and its reverse (34102121201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10212120143 - 210 = 10212119119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10212140143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106060071 + 5106060072.
It is an arithmetic number, because the mean of its divisors is an integer number (5106060072).
Almost surely, 210212120143 is an apocalyptic number.
10212120143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212120143 is an equidigital number, since it uses as much as digits as its factorization.
10212120143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 10212120143 its reverse (34102121201), we get a palindrome (44314241344).
The spelling of 10212120143 in words is "ten billion, two hundred twelve million, one hundred twenty thousand, one hundred forty-three".
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