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10212122002211 is a prime number
BaseRepresentation
bin1001010010011011000111…
…1001111000001100100011
31100011021021100012110020122
42110212301321320030203
52314303411213032321
633415214543430455
72102541621535523
oct224466171701443
940137240173218
1010212122002211
113287a33705968
12118b216bb542b
13590cca98756c
142743ab109683
1512a9926d68ab
hex949b1e78323

10212122002211 has 2 divisors, whose sum is σ = 10212122002212. Its totient is φ = 10212122002210.

The previous prime is 10212122002169. The next prime is 10212122002213. The reversal of 10212122002211 is 11220022121201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10212122002211 - 222 = 10212117807907 is a prime.

Together with 10212122002213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10212122002211.

It is not a weakly prime, because it can be changed into another prime (10212122002213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106061001105 + 5106061001106.

It is an arithmetic number, because the mean of its divisors is an integer number (5106061001106).

Almost surely, 210212122002211 is an apocalyptic number.

10212122002211 is a deficient number, since it is larger than the sum of its proper divisors (1).

10212122002211 is an equidigital number, since it uses as much as digits as its factorization.

10212122002211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 10212122002211 its reverse (11220022121201), we get a palindrome (21432144123412).

The spelling of 10212122002211 in words is "ten trillion, two hundred twelve billion, one hundred twenty-two million, two thousand, two hundred eleven".