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10212415655411 is a prime number
BaseRepresentation
bin1001010010011100001101…
…1010000100110111110011
31100011022000210202120201002
42110213003122010313303
52314310011401433121
633415304033432215
72102552115542354
oct224470332046763
940138023676632
1010212415655411
113288074444962
12118b29940b66b
13591046772558
142743d8109d2b
1512a9ad38ee0b
hex949c3684df3

10212415655411 has 2 divisors, whose sum is σ = 10212415655412. Its totient is φ = 10212415655410.

The previous prime is 10212415655399. The next prime is 10212415655413. The reversal of 10212415655411 is 11455651421201.

10212415655411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10212415655411 - 222 = 10212411461107 is a prime.

Together with 10212415655413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10212415655413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106207827705 + 5106207827706.

It is an arithmetic number, because the mean of its divisors is an integer number (5106207827706).

Almost surely, 210212415655411 is an apocalyptic number.

10212415655411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10212415655411 is an equidigital number, since it uses as much as digits as its factorization.

10212415655411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48000, while the sum is 38.

The spelling of 10212415655411 in words is "ten trillion, two hundred twelve billion, four hundred fifteen million, six hundred fifty-five thousand, four hundred eleven".