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1021311044431 is a prime number
BaseRepresentation
bin11101101110010101110…
…00011100101101001111
310121122011220220122120221
432313022320130231033
5113213121111410211
62101103412052211
7133534016432626
oct16671270345517
93548156818527
101021311044431
11364154506007
12145b2b004067
13754034774c2
14376088c66bd
151b877654c71
hexedcae1cb4f

1021311044431 has 2 divisors, whose sum is σ = 1021311044432. Its totient is φ = 1021311044430.

The previous prime is 1021311044423. The next prime is 1021311044459. The reversal of 1021311044431 is 1344401131201.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1021311044431 - 23 = 1021311044423 is a prime.

It is a super-2 number, since 2×10213110444312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1021311044396 and 1021311044405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1021311044401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510655522215 + 510655522216.

It is an arithmetic number, because the mean of its divisors is an integer number (510655522216).

Almost surely, 21021311044431 is an apocalyptic number.

1021311044431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021311044431 is an equidigital number, since it uses as much as digits as its factorization.

1021311044431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1021311044431 its reverse (1344401131201), we get a palindrome (2365712175632).

The spelling of 1021311044431 in words is "one trillion, twenty-one billion, three hundred eleven million, forty-four thousand, four hundred thirty-one".