Base | Representation |
---|---|
bin | 101111100011110011… |
… | …0011110011101000000 |
3 | 100202121211020222011201 |
4 | 1133013212132131000 |
5 | 3133132022000000 |
6 | 114530320350544 |
7 | 10243644114253 |
oct | 1370746363500 |
9 | 322554228151 |
10 | 102133000000 |
11 | 3a350463619 |
12 | 17964175454 |
13 | 98286b2c15 |
14 | 4d2c45b09a |
15 | 29cb61e96a |
hex | 17c799e740 |
102133000000 has 196 divisors, whose sum is σ = 255931489660. Its totient is φ = 40435200000.
The previous prime is 102132999977. The next prime is 102133000003. The reversal of 102133000000 is 331201.
It can be written as a sum of positive squares in 14 ways, for example, as 69438574144 + 32694425856 = 263512^2 + 180816^2 .
It is a super-2 number, since 2×1021330000002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (10).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102133000003) by changing a digit.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 108999532 + ... + 109000468.
Almost surely, 2102133000000 is an apocalyptic number.
102133000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 102133000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (127965744830).
102133000000 is an abundant number, since it is smaller than the sum of its proper divisors (153798489660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
102133000000 is an frugal number, since it uses more digits than its factorization.
102133000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1088 (or 1053 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 10.
Adding to 102133000000 its reverse (331201), we get a palindrome (102133331201).
The spelling of 102133000000 in words is "one hundred two billion, one hundred thirty-three million", and thus it is an aban number.
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