Base | Representation |
---|---|
bin | 10011000001111111… |
… | …00010001101110111 |
3 | 222101001110200000022 |
4 | 21200333202031313 |
5 | 131411100440201 |
6 | 4405502035355 |
7 | 511122534353 |
oct | 114077421567 |
9 | 28331420008 |
10 | 10217202551 |
11 | 4373387556 |
12 | 1b91878b5b |
13 | c6a9b87aa |
14 | 6ccd42463 |
15 | 3ebeb441b |
hex | 260fe2377 |
10217202551 has 2 divisors, whose sum is σ = 10217202552. Its totient is φ = 10217202550.
The previous prime is 10217202493. The next prime is 10217202553. The reversal of 10217202551 is 15520271201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10217202551 is a prime.
Together with 10217202553, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10217202551.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10217202553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5108601275 + 5108601276.
It is an arithmetic number, because the mean of its divisors is an integer number (5108601276).
Almost surely, 210217202551 is an apocalyptic number.
10217202551 is a deficient number, since it is larger than the sum of its proper divisors (1).
10217202551 is an equidigital number, since it uses as much as digits as its factorization.
10217202551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1400, while the sum is 26.
Adding to 10217202551 its reverse (15520271201), we get a palindrome (25737473752).
The spelling of 10217202551 in words is "ten billion, two hundred seventeen million, two hundred two thousand, five hundred fifty-one".
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