Base | Representation |
---|---|
bin | 11101110001101110101… |
… | …11110101110101001011 |
3 | 10121210212202212210122111 |
4 | 32320313113311311023 |
5 | 113230333042310011 |
6 | 2102004152403151 |
7 | 133630100551126 |
oct | 16706727656513 |
9 | 3553782783574 |
10 | 1023131213131 |
11 | 3649a8995765 |
12 | 1463586a64b7 |
13 | 756335a96c1 |
14 | 3773c52d3bd |
15 | 1b932344121 |
hex | ee375f5d4b |
1023131213131 has 2 divisors, whose sum is σ = 1023131213132. Its totient is φ = 1023131213130.
The previous prime is 1023131213129. The next prime is 1023131213197. The reversal of 1023131213131 is 1313121313201.
It is a weak prime.
It is an emirp because it is prime and its reverse (1313121313201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1023131213131 - 21 = 1023131213129 is a prime.
It is a super-2 number, since 2×10231312131312 (a number of 25 digits) contains 22 as substring.
Together with 1023131213129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1023131213431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511565606565 + 511565606566.
It is an arithmetic number, because the mean of its divisors is an integer number (511565606566).
Almost surely, 21023131213131 is an apocalyptic number.
1023131213131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1023131213131 is an equidigital number, since it uses as much as digits as its factorization.
1023131213131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1023131213131 its reverse (1313121313201), we get a palindrome (2336252526332).
The spelling of 1023131213131 in words is "one trillion, twenty-three billion, one hundred thirty-one million, two hundred thirteen thousand, one hundred thirty-one".
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