Base | Representation |
---|---|
bin | 11101110001101110101… |
… | …11110101111001110111 |
3 | 10121210212202212211001121 |
4 | 32320313113311321313 |
5 | 113230333042312211 |
6 | 2102004152404411 |
7 | 133630100552035 |
oct | 16706727657167 |
9 | 3553782784047 |
10 | 1023131213431 |
11 | 3649a8995a08 |
12 | 1463586a6707 |
13 | 756335a9892 |
14 | 3773c52d555 |
15 | 1b932344271 |
hex | ee375f5e77 |
1023131213431 has 2 divisors, whose sum is σ = 1023131213432. Its totient is φ = 1023131213430.
The previous prime is 1023131213393. The next prime is 1023131213441. The reversal of 1023131213431 is 1343121313201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1023131213431 - 27 = 1023131213303 is a prime.
It is a super-2 number, since 2×10231312134312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1023131213396 and 1023131213405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1023131213441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511565606715 + 511565606716.
It is an arithmetic number, because the mean of its divisors is an integer number (511565606716).
Almost surely, 21023131213431 is an apocalyptic number.
1023131213431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1023131213431 is an equidigital number, since it uses as much as digits as its factorization.
1023131213431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1023131213431 its reverse (1343121313201), we get a palindrome (2366252526632).
The spelling of 1023131213431 in words is "one trillion, twenty-three billion, one hundred thirty-one million, two hundred thirteen thousand, four hundred thirty-one".
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