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10235140117 is a prime number
BaseRepresentation
bin10011000100000111…
…11101100000010101
3222102022012222201121
421202003331200111
5131430143440432
64411342323541
7511431153436
oct114203754025
928368188647
1010235140117
114382519294
121b978895b1
13c71629237
146d149148d
153ed859197
hex2620fd815

10235140117 has 2 divisors, whose sum is σ = 10235140118. Its totient is φ = 10235140116.

The previous prime is 10235140087. The next prime is 10235140183. The reversal of 10235140117 is 71104153201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10230513316 + 4626801 = 101146^2 + 2151^2 .

It is a cyclic number.

It is not a de Polignac number, because 10235140117 - 27 = 10235139989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10235140091 and 10235140100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10235140187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5117570058 + 5117570059.

It is an arithmetic number, because the mean of its divisors is an integer number (5117570059).

Almost surely, 210235140117 is an apocalyptic number.

It is an amenable number.

10235140117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10235140117 is an equidigital number, since it uses as much as digits as its factorization.

10235140117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

Adding to 10235140117 its reverse (71104153201), we get a palindrome (81339293318).

The spelling of 10235140117 in words is "ten billion, two hundred thirty-five million, one hundred forty thousand, one hundred seventeen".