Base | Representation |
---|---|
bin | 101111101011111000… |
… | …1111001110110101101 |
3 | 100210022202000002212222 |
4 | 1133113301321312231 |
5 | 3134211013300102 |
6 | 115013254205125 |
7 | 10253451206141 |
oct | 1372761716655 |
9 | 323282002788 |
10 | 102404431277 |
11 | 3a47a6a4995 |
12 | 17a1b0537a5 |
13 | 986c9ba345 |
14 | 4d56515221 |
15 | 29e5388aa2 |
hex | 17d7c79dad |
102404431277 has 2 divisors, whose sum is σ = 102404431278. Its totient is φ = 102404431276.
The previous prime is 102404431189. The next prime is 102404431279. The reversal of 102404431277 is 772134404201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78748145641 + 23656285636 = 280621^2 + 153806^2 .
It is a cyclic number.
It is not a de Polignac number, because 102404431277 - 210 = 102404430253 is a prime.
Together with 102404431279, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102404431279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51202215638 + 51202215639.
It is an arithmetic number, because the mean of its divisors is an integer number (51202215639).
Almost surely, 2102404431277 is an apocalyptic number.
It is an amenable number.
102404431277 is a deficient number, since it is larger than the sum of its proper divisors (1).
102404431277 is an equidigital number, since it uses as much as digits as its factorization.
102404431277 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 37632, while the sum is 35.
Adding to 102404431277 its reverse (772134404201), we get a palindrome (874538835478).
The spelling of 102404431277 in words is "one hundred two billion, four hundred four million, four hundred thirty-one thousand, two hundred seventy-seven".
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