10254407 has 2 divisors, whose sum is σ = 10254408. Its totient is φ = 10254406.

The previous prime is 10254403. The next prime is 10254421. The reversal of 10254407 is 70445201.

10254407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (70445201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10254407 - 2² = 10254403 is a prime.

It is a Chen prime.

It is equal to p₆₈₀₃₅₁ and since 10254407 and 680351 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10254403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5127203 + 5127204.

It is an arithmetic number, because the mean of its divisors is an integer number (5127204).

Almost surely, 2^10254407 is an apocalyptic number.

10254407 is a deficient number, since it is larger than the sum of its proper divisors (1).

10254407 is an equidigital number, since it uses as much as digits as its factorization.

10254407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1120, while the sum is 23.

The square root of 10254407 is about 3202.2503025217. The cubic root of 10254407 is about 217.2552017463.

Adding to 10254407 its reverse (70445201), we get a palindrome (80699608).

The spelling of 10254407 in words is "ten million, two hundred fifty-four thousand, four hundred seven".