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10292500479851 is a prime number
BaseRepresentation
bin1001010111000110100011…
…0101011011111101101011
31100102221202001111011221222
42111301220311123331223
52322113020110323401
633520150501252255
72111415520402502
oct225615065337553
940387661434858
1010292500479851
113309030217887
1211a290970408b
1359876a336635
14278234245839
1512cae9016c1b
hex95c68d5bf6b

10292500479851 has 2 divisors, whose sum is σ = 10292500479852. Its totient is φ = 10292500479850.

The previous prime is 10292500479847. The next prime is 10292500479853. The reversal of 10292500479851 is 15897400529201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10292500479851 - 22 = 10292500479847 is a prime.

It is a super-2 number, since 2×102925004798512 (a number of 27 digits) contains 22 as substring.

Together with 10292500479853, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10292500479793 and 10292500479802.

It is not a weakly prime, because it can be changed into another prime (10292500479853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5146250239925 + 5146250239926.

It is an arithmetic number, because the mean of its divisors is an integer number (5146250239926).

Almost surely, 210292500479851 is an apocalyptic number.

10292500479851 is a deficient number, since it is larger than the sum of its proper divisors (1).

10292500479851 is an equidigital number, since it uses as much as digits as its factorization.

10292500479851 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1814400, while the sum is 53.

The spelling of 10292500479851 in words is "ten trillion, two hundred ninety-two billion, five hundred million, four hundred seventy-nine thousand, eight hundred fifty-one".