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103001312211071 is a prime number
BaseRepresentation
bin10111011010110111011100…
…101000000011000001111111
3111111200211101112202000220212
4113122313130220003001333
5102000033141411223241
61003022052151303035
730460412352045521
oct2732673450030177
9444624345660825
10103001312211071
112a90167a56050a
12b67641707aa7b
134561c9c797bb1
141b6140c0c7a11
15bd9479316beb
hex5daddca0307f

103001312211071 has 2 divisors, whose sum is σ = 103001312211072. Its totient is φ = 103001312211070.

The previous prime is 103001312211067. The next prime is 103001312211073. The reversal of 103001312211071 is 170112213100301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103001312211071 - 22 = 103001312211067 is a prime.

Together with 103001312211073, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103001312211073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51500656105535 + 51500656105536.

It is an arithmetic number, because the mean of its divisors is an integer number (51500656105536).

Almost surely, 2103001312211071 is an apocalyptic number.

103001312211071 is a deficient number, since it is larger than the sum of its proper divisors (1).

103001312211071 is an equidigital number, since it uses as much as digits as its factorization.

103001312211071 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 103001312211071 its reverse (170112213100301), we get a palindrome (273113525311372).

The spelling of 103001312211071 in words is "one hundred three trillion, one billion, three hundred twelve million, two hundred eleven thousand, seventy-one".