1030130011319 has 2 divisors, whose sum is σ = 1030130011320. Its totient is φ = 1030130011318.

The previous prime is 1030130011291. The next prime is 1030130011321. The reversal of 1030130011319 is 9131100310301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1030130011319 - 2¹⁶ = 1030129945783 is a prime.

It is a super-2 number, since 2×1030130011319² (a number of 25 digits) contains 22 as substring.

Together with 1030130011321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1030130011294 and 1030130011303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1030130011219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515065005659 + 515065005660.

It is an arithmetic number, because the mean of its divisors is an integer number (515065005660).

Almost surely, 2^{1030130011319} is an apocalyptic number.

1030130011319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030130011319 is an equidigital number, since it uses as much as digits as its factorization.

1030130011319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 23.

The spelling of 1030130011319 in words is "one trillion, thirty billion, one hundred thirty million, eleven thousand, three hundred nineteen".