Search a number
-
+
1030223200007 is a prime number
BaseRepresentation
bin11101111110111100001…
…01100111111100000111
310122111012000201001201002
432333132011213330013
5113334344114400012
62105140014323515
7134300614466531
oct16773605477407
93574160631632
101030223200007
11367a08158441
121477b77b959b
13761c397ba41
1437c12392851
151bbe9c7d7c2
hexefde167f07

1030223200007 has 2 divisors, whose sum is σ = 1030223200008. Its totient is φ = 1030223200006.

The previous prime is 1030223199979. The next prime is 1030223200009. The reversal of 1030223200007 is 7000023220301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1030223200007 - 222 = 1030219005703 is a prime.

It is a super-2 number, since 2×10302232000072 (a number of 25 digits) contains 22 as substring.

Together with 1030223200009, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1030223200009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515111600003 + 515111600004.

It is an arithmetic number, because the mean of its divisors is an integer number (515111600004).

Almost surely, 21030223200007 is an apocalyptic number.

1030223200007 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030223200007 is an equidigital number, since it uses as much as digits as its factorization.

1030223200007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 20.

Adding to 1030223200007 its reverse (7000023220301), we get a palindrome (8030246420308).

The spelling of 1030223200007 in words is "one trillion, thirty billion, two hundred twenty-three million, two hundred thousand, seven".