Base | Representation |
---|---|
bin | 11101111110111101001… |
… | …11001111010101000011 |
3 | 10122111012122021202121212 |
4 | 32333132213033111003 |
5 | 113334403343341344 |
6 | 2105140531240335 |
7 | 134301052421003 |
oct | 16773647172503 |
9 | 3574178252555 |
10 | 1030232012099 |
11 | 367a12127064 |
12 | 1477ba7490ab |
13 | 761c57459b4 |
14 | 37c13608003 |
15 | 1bbea91e79e |
hex | efde9cf543 |
1030232012099 has 2 divisors, whose sum is σ = 1030232012100. Its totient is φ = 1030232012098.
The previous prime is 1030232012087. The next prime is 1030232012111. The reversal of 1030232012099 is 9902102320301.
It is a balanced prime because it is at equal distance from previous prime (1030232012087) and next prime (1030232012111).
It is an emirp because it is prime and its reverse (9902102320301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1030232012099 - 28 = 1030232011843 is a prime.
It is a super-2 number, since 2×10302320120992 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1030232012399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515116006049 + 515116006050.
It is an arithmetic number, because the mean of its divisors is an integer number (515116006050).
Almost surely, 21030232012099 is an apocalyptic number.
1030232012099 is a deficient number, since it is larger than the sum of its proper divisors (1).
1030232012099 is an equidigital number, since it uses as much as digits as its factorization.
1030232012099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 32.
The spelling of 1030232012099 in words is "one trillion, thirty billion, two hundred thirty-two million, twelve thousand, ninety-nine".
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