Base | Representation |
---|---|
bin | 10111011011010110000000… |
… | …101110000001110011100011 |
3 | 111111210222002200020010102121 |
4 | 113123112000232001303203 |
5 | 102001102344240412121 |
6 | 1003045120442525111 |
7 | 30462653535546532 |
oct | 2733260056016343 |
9 | 444728080203377 |
10 | 103034130013411 |
11 | 2a914590331103 |
12 | b680855806797 |
13 | 45650cc88124c |
14 | 1b62c4286c319 |
15 | bda24a4e5141 |
hex | 5db580b81ce3 |
103034130013411 has 2 divisors, whose sum is σ = 103034130013412. Its totient is φ = 103034130013410.
The previous prime is 103034130013363. The next prime is 103034130013459. The reversal of 103034130013411 is 114310031430301.
It is a balanced prime because it is at equal distance from previous prime (103034130013363) and next prime (103034130013459).
It is a cyclic number.
It is not a de Polignac number, because 103034130013411 - 241 = 100835106757859 is a prime.
It is not a weakly prime, because it can be changed into another prime (103034130013481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51517065006705 + 51517065006706.
It is an arithmetic number, because the mean of its divisors is an integer number (51517065006706).
Almost surely, 2103034130013411 is an apocalyptic number.
103034130013411 is a deficient number, since it is larger than the sum of its proper divisors (1).
103034130013411 is an equidigital number, since it uses as much as digits as its factorization.
103034130013411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 103034130013411 its reverse (114310031430301), we get a palindrome (217344161443712).
The spelling of 103034130013411 in words is "one hundred three trillion, thirty-four billion, one hundred thirty million, thirteen thousand, four hundred eleven".
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