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103035541253 is a prime number
BaseRepresentation
bin101111111110101100…
…1011001011100000101
3100211221201112211000112
41133331121121130011
53142004044310003
6115200041122405
710305213436001
oct1377531313405
9324851484015
10103035541253
113a773971187
1217b76489405
1399406891b8
144db6279701
152a3099e3d8
hex17fd659705

103035541253 has 2 divisors, whose sum is σ = 103035541254. Its totient is φ = 103035541252.

The previous prime is 103035541223. The next prime is 103035541267. The reversal of 103035541253 is 352145530301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96274919524 + 6760621729 = 310282^2 + 82223^2 .

It is a cyclic number.

It is not a de Polignac number, because 103035541253 - 28 = 103035540997 is a prime.

It is a super-2 number, since 2×1030355412532 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103035541223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51517770626 + 51517770627.

It is an arithmetic number, because the mean of its divisors is an integer number (51517770627).

Almost surely, 2103035541253 is an apocalyptic number.

It is an amenable number.

103035541253 is a deficient number, since it is larger than the sum of its proper divisors (1).

103035541253 is an equidigital number, since it uses as much as digits as its factorization.

103035541253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 32.

The spelling of 103035541253 in words is "one hundred three billion, thirty-five million, five hundred forty-one thousand, two hundred fifty-three".