Base | Representation |
---|---|
bin | 11110000000011010001… |
… | …10101101000111011101 |
3 | 10122120012222222220000221 |
4 | 33000031012231013131 |
5 | 113343003033400014 |
6 | 2105350153321341 |
7 | 134326303336453 |
oct | 17001506550735 |
9 | 3576188886027 |
10 | 1031012012509 |
11 | 3682824479a6 |
12 | 147997a06251 |
13 | 762bb2156bb |
14 | 37c890489d3 |
15 | 1bc44145b24 |
hex | f00d1ad1dd |
1031012012509 has 2 divisors, whose sum is σ = 1031012012510. Its totient is φ = 1031012012508.
The previous prime is 1031012012461. The next prime is 1031012012587. The reversal of 1031012012509 is 9052102101301.
1031012012509 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 732142056409 + 298869956100 = 855653^2 + 546690^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031012012509 - 213 = 1031012004317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031012012209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515506006254 + 515506006255.
It is an arithmetic number, because the mean of its divisors is an integer number (515506006255).
Almost surely, 21031012012509 is an apocalyptic number.
It is an amenable number.
1031012012509 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031012012509 is an equidigital number, since it uses as much as digits as its factorization.
1031012012509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
The spelling of 1031012012509 in words is "one trillion, thirty-one billion, twelve million, twelve thousand, five hundred nine".
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