Base | Representation |
---|---|
bin | 10011001101000101… |
… | …01111111111111111 |
3 | 222121112200112022102 |
4 | 21212202233333333 |
5 | 132103420221002 |
6 | 4423025535315 |
7 | 513333163232 |
oct | 114642577777 |
9 | 28545615272 |
10 | 10310320127 |
11 | 44109a8128 |
12 | 1bb8aa453b |
13 | c8408c753 |
14 | 6db461419 |
15 | 405259a02 |
hex | 2668affff |
10310320127 has 2 divisors, whose sum is σ = 10310320128. Its totient is φ = 10310320126.
The previous prime is 10310320109. The next prime is 10310320171. The reversal of 10310320127 is 72102301301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10310320127 - 232 = 6015352831 is a prime.
It is a super-2 number, since 2×103103201272 (a number of 21 digits) contains 22 as substring.
It is a plaindrome in base 16.
It is a junction number, because it is equal to n+sod(n) for n = 10310320099 and 10310320108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10310320177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155160063 + 5155160064.
It is an arithmetic number, because the mean of its divisors is an integer number (5155160064).
Almost surely, 210310320127 is an apocalyptic number.
10310320127 is a deficient number, since it is larger than the sum of its proper divisors (1).
10310320127 is an equidigital number, since it uses as much as digits as its factorization.
10310320127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 10310320127 its reverse (72102301301), we get a palindrome (82412621428).
The spelling of 10310320127 in words is "ten billion, three hundred ten million, three hundred twenty thousand, one hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •