Base | Representation |
---|---|
bin | 110000000000111101… |
… | …0011110100110010000 |
3 | 100212011000010212122212 |
4 | 1200001322132212100 |
5 | 3142132444301000 |
6 | 115211345251252 |
7 | 10310123530061 |
oct | 1400172364620 |
9 | 325130125585 |
10 | 103111322000 |
11 | 3a8027203a5 |
12 | 17b97933b28 |
13 | 995329cc8b |
14 | 4dc2364568 |
15 | 2a3746cc35 |
hex | 1801e9e990 |
103111322000 has 40 divisors (see below), whose sum is σ = 249323181432. Its totient is φ = 41244528000.
The previous prime is 103111321997. The next prime is 103111322021. The reversal of 103111322000 is 223111301.
103111322000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 28558296064 + 74553025936 = 168992^2 + 273044^2 .
It is a tau number, because it is divible by the number of its divisors (40).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25775831 + ... + 25779830.
Almost surely, 2103111322000 is an apocalyptic number.
103111322000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
103111322000 is an abundant number, since it is smaller than the sum of its proper divisors (146211859432).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103111322000 is an equidigital number, since it uses as much as digits as its factorization.
103111322000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51555684 (or 51555668 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 103111322000 its reverse (223111301), we get a palindrome (103334433301).
The spelling of 103111322000 in words is "one hundred three billion, one hundred eleven million, three hundred twenty-two thousand".
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