Base | Representation |
---|---|
bin | 11110000000101000010… |
… | …01001101110101000100 |
3 | 10122120112020012221010020 |
4 | 33000110021031311010 |
5 | 113343223302030200 |
6 | 2105410012455140 |
7 | 134332236222012 |
oct | 17002411156504 |
9 | 3576466187106 |
10 | 1031130111300 |
11 | 368333080303 |
12 | 147a0b47a4b0 |
13 | 76309825143 |
14 | 37c9a9cb8b2 |
15 | 1bc4e6c2ea0 |
hex | f01424dd44 |
1031130111300 has 36 divisors (see below), whose sum is σ = 2983403122896. Its totient is φ = 274968029600.
The previous prime is 1031130111217. The next prime is 1031130111313. The reversal of 1031130111300 is 31110311301.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1031130111300.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1718549886 + ... + 1718550485.
Almost surely, 21031130111300 is an apocalyptic number.
1031130111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1031130111300 is an abundant number, since it is smaller than the sum of its proper divisors (1952273011596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1031130111300 is a wasteful number, since it uses less digits than its factorization.
1031130111300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3437100388 (or 3437100381 counting only the distinct ones).
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 1031130111300 its reverse (31110311301), we get a palindrome (1062240422601).
The spelling of 1031130111300 in words is "one trillion, thirty-one billion, one hundred thirty million, one hundred eleven thousand, three hundred".
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