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103113113137 is a prime number
BaseRepresentation
bin110000000001000000…
…1010011111000110001
3100212011010111212122021
41200002001103320301
53142133424110022
6115211451511441
710310145000046
oct1400201237061
9325133455567
10103113113137
113a803734081
1217b98458581
139953779318
144dc26ad1cd
152a376c37c7
hex1802053e31

103113113137 has 2 divisors, whose sum is σ = 103113113138. Its totient is φ = 103113113136.

The previous prime is 103113113111. The next prime is 103113113143. The reversal of 103113113137 is 731311311301.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93034760256 + 10078352881 = 305016^2 + 100391^2 .

It is an emirp because it is prime and its reverse (731311311301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103113113137 - 27 = 103113113009 is a prime.

It is not a weakly prime, because it can be changed into another prime (103113113237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51556556568 + 51556556569.

It is an arithmetic number, because the mean of its divisors is an integer number (51556556569).

Almost surely, 2103113113137 is an apocalyptic number.

It is an amenable number.

103113113137 is a deficient number, since it is larger than the sum of its proper divisors (1).

103113113137 is an equidigital number, since it uses as much as digits as its factorization.

103113113137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 567, while the sum is 25.

Adding to 103113113137 its reverse (731311311301), we get a palindrome (834424424438).

The spelling of 103113113137 in words is "one hundred three billion, one hundred thirteen million, one hundred thirteen thousand, one hundred thirty-seven".