Base | Representation |
---|---|
bin | 1001011000001111010011… |
… | …1001100100110100010001 |
3 | 1100111211011010012000001021 |
4 | 2112003310321210310101 |
5 | 2322423014220302423 |
6 | 33533140432035441 |
7 | 2113006502556643 |
oct | 226036471446421 |
9 | 40454133160037 |
10 | 10312030244113 |
11 | 3316342269824 |
12 | 11a665a092b81 |
13 | 59a56047aa70 |
14 | 279167cc2893 |
15 | 12d38d84895d |
hex | 960f4e64d11 |
10312030244113 has 64 divisors (see below), whose sum is σ = 11792675220480. Its totient is φ = 8950304563200.
The previous prime is 10312030244057. The next prime is 10312030244123. The reversal of 10312030244113 is 31144203021301.
It is not a de Polignac number, because 10312030244113 - 237 = 10174591290641 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10312030244123) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1394833345 + ... + 1394840737.
It is an arithmetic number, because the mean of its divisors is an integer number (184260550320).
Almost surely, 210312030244113 is an apocalyptic number.
10312030244113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10312030244113 is a deficient number, since it is larger than the sum of its proper divisors (1480644976367).
10312030244113 is a wasteful number, since it uses less digits than its factorization.
10312030244113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8090.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 10312030244113 its reverse (31144203021301), we get a palindrome (41456233265414).
The spelling of 10312030244113 in words is "ten trillion, three hundred twelve billion, thirty million, two hundred forty-four thousand, one hundred thirteen".
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