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1031213231130 = 23534373774371
BaseRepresentation
bin11110000000110010001…
…10010010110000011010
310122120202000121212002110
433000121012102300122
5113343411041344010
62105422142213150
7134334265560615
oct17003106226032
93576660555073
101031213231130
11368375a92485
12147a332841b6
1376320b08584
1437ca7a6717c
151bc56b41120
hexf019192c1a

1031213231130 has 16 divisors (see below), whose sum is σ = 2474911754784. Its totient is φ = 274990194960.

The previous prime is 1031213231123. The next prime is 1031213231159. The reversal of 1031213231130 is 311323121301.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 1031213231097 and 1031213231106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17186887156 + ... + 17186887215.

It is an arithmetic number, because the mean of its divisors is an integer number (154681984674).

Almost surely, 21031213231130 is an apocalyptic number.

1031213231130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1031213231130 is an abundant number, since it is smaller than the sum of its proper divisors (1443698523654).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1031213231130 is a wasteful number, since it uses less digits than its factorization.

1031213231130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34373774381.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 1031213231130 its reverse (311323121301), we get a palindrome (1342536352431).

The spelling of 1031213231130 in words is "one trillion, thirty-one billion, two hundred thirteen million, two hundred thirty-one thousand, one hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 34373774371 68747548742 103121323113 171868871855 206242646226 343737743710 515606615565 1031213231130