Base | Representation |
---|---|
bin | 10011001101010011… |
… | …11011100000110101 |
3 | 222121200020011011021 |
4 | 21212221323200311 |
5 | 132104410433133 |
6 | 4423134141141 |
7 | 513355162501 |
oct | 114651734065 |
9 | 28550204137 |
10 | 10312202293 |
11 | 4411a73238 |
12 | 1bb96517b1 |
13 | c8459b363 |
14 | 6db7d1301 |
15 | 4054cc52d |
hex | 266a7b835 |
10312202293 has 2 divisors, whose sum is σ = 10312202294. Its totient is φ = 10312202292.
The previous prime is 10312202189. The next prime is 10312202309. The reversal of 10312202293 is 39220221301.
10312202293 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10148950564 + 163251729 = 100742^2 + 12777^2 .
It is a cyclic number.
It is not a de Polignac number, because 10312202293 - 217 = 10312071221 is a prime.
It is a super-2 number, since 2×103122022932 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10312202393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156101146 + 5156101147.
It is an arithmetic number, because the mean of its divisors is an integer number (5156101147).
Almost surely, 210312202293 is an apocalyptic number.
It is an amenable number.
10312202293 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312202293 is an equidigital number, since it uses as much as digits as its factorization.
10312202293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 10312202293 its reverse (39220221301), we get a palindrome (49532423594).
The spelling of 10312202293 in words is "ten billion, three hundred twelve million, two hundred two thousand, two hundred ninety-three".
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