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10312251307 is a prime number
BaseRepresentation
bin10011001101010100…
…00111011110101011
3222121200022122101121
421212222013132223
5132104414020212
64423135200111
7513355455421
oct114652073653
928550278347
1010312251307
114411aa7046
121bb9676037
13c845b7767
146db805111
154054dbd07
hex266a877ab

10312251307 has 2 divisors, whose sum is σ = 10312251308. Its totient is φ = 10312251306.

The previous prime is 10312251263. The next prime is 10312251329. The reversal of 10312251307 is 70315221301.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10312251307 is a prime.

It is not a weakly prime, because it can be changed into another prime (10312251337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156125653 + 5156125654.

It is an arithmetic number, because the mean of its divisors is an integer number (5156125654).

Almost surely, 210312251307 is an apocalyptic number.

10312251307 is a deficient number, since it is larger than the sum of its proper divisors (1).

10312251307 is an equidigital number, since it uses as much as digits as its factorization.

10312251307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 25.

Adding to 10312251307 its reverse (70315221301), we get a palindrome (80627472608).

The spelling of 10312251307 in words is "ten billion, three hundred twelve million, two hundred fifty-one thousand, three hundred seven".