Base | Representation |
---|---|
bin | 10111011100101000111001… |
… | …000100101101010001110111 |
3 | 111112010110210200221022111222 |
4 | 113130220321010231101313 |
5 | 102004032123302443221 |
6 | 1003154035224420555 |
7 | 30502254050606153 |
oct | 2734507104552167 |
9 | 445113720838458 |
10 | 103123122312311 |
11 | 2a9492a8149472 |
12 | b695b5101775b |
13 | 457061299ac8a |
14 | 1b672859b6063 |
15 | bdc70816d9ab |
hex | 5dca3912d477 |
103123122312311 has 2 divisors, whose sum is σ = 103123122312312. Its totient is φ = 103123122312310.
The previous prime is 103123122312281. The next prime is 103123122312337. The reversal of 103123122312311 is 113213221321301.
It is an a-pointer prime, because the next prime (103123122312337) can be obtained adding 103123122312311 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103123122312311 - 214 = 103123122295927 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103123122312211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51561561156155 + 51561561156156.
It is an arithmetic number, because the mean of its divisors is an integer number (51561561156156).
Almost surely, 2103123122312311 is an apocalyptic number.
103123122312311 is a deficient number, since it is larger than the sum of its proper divisors (1).
103123122312311 is an equidigital number, since it uses as much as digits as its factorization.
103123122312311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 103123122312311 its reverse (113213221321301), we get a palindrome (216336343633612).
The spelling of 103123122312311 in words is "one hundred three trillion, one hundred twenty-three billion, one hundred twenty-two million, three hundred twelve thousand, three hundred eleven".
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