Base | Representation |
---|---|
bin | 1001011000010000011011… |
… | …0001100011001001100111 |
3 | 1100111211221000110210011211 |
4 | 2112010012301203021213 |
5 | 2322424123003130043 |
6 | 33533230303412251 |
7 | 2113020103552615 |
oct | 226040661431147 |
9 | 40454830423154 |
10 | 10312330130023 |
11 | 3316486575519 |
12 | 11a67225b4087 |
13 | 59a5aa63894c |
14 | 279195a666b5 |
15 | 12d3a9d33a9d |
hex | 96106c63267 |
10312330130023 has 2 divisors, whose sum is σ = 10312330130024. Its totient is φ = 10312330130022.
The previous prime is 10312330130009. The next prime is 10312330130051. The reversal of 10312330130023 is 32003103321301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10312330130023 - 25 = 10312330129991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10312330129976 and 10312330130003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10312330131023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156165065011 + 5156165065012.
It is an arithmetic number, because the mean of its divisors is an integer number (5156165065012).
Almost surely, 210312330130023 is an apocalyptic number.
10312330130023 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312330130023 is an equidigital number, since it uses as much as digits as its factorization.
10312330130023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 10312330130023 its reverse (32003103321301), we get a palindrome (42315433451324).
The spelling of 10312330130023 in words is "ten trillion, three hundred twelve billion, three hundred thirty million, one hundred thirty thousand, twenty-three".
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