Base | Representation |
---|---|
bin | 110000000001010110… |
… | …0011010101011010101 |
3 | 100212011220202222022221 |
4 | 1200002230122223111 |
5 | 3142144322210031 |
6 | 115212534022341 |
7 | 10310343022501 |
oct | 1400254325325 |
9 | 325156688287 |
10 | 103124413141 |
11 | 3a80a051a22 |
12 | 17ba01a79b1 |
13 | 9955c04809 |
14 | 4dc3db1301 |
15 | 2a386a6a11 |
hex | 1802b1aad5 |
103124413141 has 2 divisors, whose sum is σ = 103124413142. Its totient is φ = 103124413140.
The previous prime is 103124413121. The next prime is 103124413157. The reversal of 103124413141 is 141314421301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102434562916 + 689850225 = 320054^2 + 26265^2 .
It is a cyclic number.
It is not a de Polignac number, because 103124413141 - 225 = 103090858709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103124413121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51562206570 + 51562206571.
It is an arithmetic number, because the mean of its divisors is an integer number (51562206571).
Almost surely, 2103124413141 is an apocalyptic number.
It is an amenable number.
103124413141 is a deficient number, since it is larger than the sum of its proper divisors (1).
103124413141 is an equidigital number, since it uses as much as digits as its factorization.
103124413141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 103124413141 its reverse (141314421301), we get a palindrome (244438834442).
The spelling of 103124413141 in words is "one hundred three billion, one hundred twenty-four million, four hundred thirteen thousand, one hundred forty-one".
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