103130011121213 has 2 divisors, whose sum is σ = 103130011121214. Its totient is φ = 103130011121212.

The previous prime is 103130011121183. The next prime is 103130011121233. The reversal of 103130011121213 is 312121110031301.

It is an a-pointer prime, because the next prime (103130011121233) can be obtained adding 103130011121213 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97979371793209 + 5150639328004 = 9898453^2 + 2269502^2 .

It is an emirp because it is prime and its reverse (312121110031301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103130011121213 - 2³⁸ = 102855133214269 is a prime.

It is a super-2 number, since 2×103130011121213² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103130011121233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565005560606 + 51565005560607.

It is an arithmetic number, because the mean of its divisors is an integer number (51565005560607).

Almost surely, 2^{103130011121213} is an apocalyptic number.

It is an amenable number.

103130011121213 is a deficient number, since it is larger than the sum of its proper divisors (1).

103130011121213 is an equidigital number, since it uses as much as digits as its factorization.

103130011121213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 103130011121213 its reverse (312121110031301), we get a palindrome (415251121152514).

The spelling of 103130011121213 in words is "one hundred three trillion, one hundred thirty billion, eleven million, one hundred twenty-one thousand, two hundred thirteen".