Base | Representation |
---|---|
bin | 11110000000111101111… |
… | …00000001001111000111 |
3 | 10122120222211222020210102 |
4 | 33000132330001033013 |
5 | 113344111131414343 |
6 | 2105440002114315 |
7 | 134336565366662 |
oct | 17003674011707 |
9 | 3576884866712 |
10 | 1031311201223 |
11 | 3684163178a6 |
12 | 147a6004b99b |
13 | 763381bb144 |
14 | 37cb6a8a6d9 |
15 | 1bc605443b8 |
hex | f01ef013c7 |
1031311201223 has 2 divisors, whose sum is σ = 1031311201224. Its totient is φ = 1031311201222.
The previous prime is 1031311201213. The next prime is 1031311201237. The reversal of 1031311201223 is 3221021131301.
It is a happy number.
1031311201223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1031311201223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1031311201195 and 1031311201204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031311201213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515655600611 + 515655600612.
It is an arithmetic number, because the mean of its divisors is an integer number (515655600612).
Almost surely, 21031311201223 is an apocalyptic number.
1031311201223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031311201223 is an equidigital number, since it uses as much as digits as its factorization.
1031311201223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1031311201223 its reverse (3221021131301), we get a palindrome (4252332332524).
The spelling of 1031311201223 in words is "one trillion, thirty-one billion, three hundred eleven million, two hundred one thousand, two hundred twenty-three".
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