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10314053250533 is a prime number
BaseRepresentation
bin1001011000010110110101…
…1110101110110111100101
31100112000101002211101010222
42112011231132232313211
52322441140113004113
633534113300054125
72113110566051564
oct226055536566745
940460332741128
1010314053250533
11331719019a45a
1211a6b23694345
1359a7c361ba96
142792ba849bdb
1512d45b252e08
hex9616d7aede5

10314053250533 has 2 divisors, whose sum is σ = 10314053250534. Its totient is φ = 10314053250532.

The previous prime is 10314053250521. The next prime is 10314053250541. The reversal of 10314053250533 is 33505235041301.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5430381981124 + 4883671269409 = 2330318^2 + 2209903^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10314053250533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10314053250493 and 10314053250502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10314053250583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157026625266 + 5157026625267.

It is an arithmetic number, because the mean of its divisors is an integer number (5157026625267).

Almost surely, 210314053250533 is an apocalyptic number.

It is an amenable number.

10314053250533 is a deficient number, since it is larger than the sum of its proper divisors (1).

10314053250533 is an equidigital number, since it uses as much as digits as its factorization.

10314053250533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81000, while the sum is 35.

Adding to 10314053250533 its reverse (33505235041301), we get a palindrome (43819288291834).

The spelling of 10314053250533 in words is "ten trillion, three hundred fourteen billion, fifty-three million, two hundred fifty thousand, five hundred thirty-three".