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103210231127 is a prime number
BaseRepresentation
bin110000000011111001…
…1110010010101010111
3100212101220020222110212
41200013303302111113
53142333304344002
6115225241240035
710312434326633
oct1400763622527
9325356228425
10103210231127
113a853537283
1218004a9301b
13996a9210a3
144dd154ddc3
152a40ea9352
hex1807cf2557

103210231127 has 2 divisors, whose sum is σ = 103210231128. Its totient is φ = 103210231126.

The previous prime is 103210231081. The next prime is 103210231129. The reversal of 103210231127 is 721132012301.

It is a strong prime.

It is an emirp because it is prime and its reverse (721132012301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103210231127 - 210 = 103210230103 is a prime.

Together with 103210231129, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103210231129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51605115563 + 51605115564.

It is an arithmetic number, because the mean of its divisors is an integer number (51605115564).

Almost surely, 2103210231127 is an apocalyptic number.

103210231127 is a deficient number, since it is larger than the sum of its proper divisors (1).

103210231127 is an equidigital number, since it uses as much as digits as its factorization.

103210231127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 103210231127 its reverse (721132012301), we get a palindrome (824342243428).

The spelling of 103210231127 in words is "one hundred three billion, two hundred ten million, two hundred thirty-one thousand, one hundred twenty-seven".