Base | Representation |
---|---|
bin | 10111011101111011111101… |
… | …001000101101010110100111 |
3 | 111112110000000102021012020021 |
4 | 113131323331020231112213 |
5 | 102012012303111311242 |
6 | 1003303025304420011 |
7 | 30511562166364426 |
oct | 2735737510552647 |
9 | 445400012235207 |
10 | 103212311041447 |
11 | 2a983105930773 |
12 | b6ab2a2177607 |
13 | 4578b576c220a |
14 | 1b6b706c532bd |
15 | bdebc8198b67 |
hex | 5ddefd22d5a7 |
103212311041447 has 2 divisors, whose sum is σ = 103212311041448. Its totient is φ = 103212311041446.
The previous prime is 103212311041421. The next prime is 103212311041561. The reversal of 103212311041447 is 744140113212301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103212311041447 - 27 = 103212311041319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103212315041447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51606155520723 + 51606155520724.
It is an arithmetic number, because the mean of its divisors is an integer number (51606155520724).
Almost surely, 2103212311041447 is an apocalyptic number.
103212311041447 is a deficient number, since it is larger than the sum of its proper divisors (1).
103212311041447 is an equidigital number, since it uses as much as digits as its factorization.
103212311041447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 34.
Adding to 103212311041447 its reverse (744140113212301), we get a palindrome (847352424253748).
The spelling of 103212311041447 in words is "one hundred three trillion, two hundred twelve billion, three hundred eleven million, forty-one thousand, four hundred forty-seven".
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