Base | Representation |
---|---|
bin | 10111011110001101101001… |
… | …101000010011000111111010 |
3 | 111112111211001120021202101120 |
4 | 113132031221220103013322 |
5 | 102012320211122144010 |
6 | 1003315450514330110 |
7 | 30513134060443050 |
oct | 2736155150230772 |
9 | 445454046252346 |
10 | 103231311131130 |
11 | 2a990175998326 |
12 | b6b2b05289936 |
13 | 457a894b91730 |
14 | 1b6c5ca4121d0 |
15 | be043b24ee70 |
hex | 5de369a131fa |
103231311131130 has 128 divisors (see below), whose sum is σ = 304933564970496. Its totient is φ = 21780375552000.
The previous prime is 103231311131101. The next prime is 103231311131147. The reversal of 103231311131130 is 31131113132301.
It is a self number, because there is not a number n which added to its sum of digits gives 103231311131130.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 241885930 + ... + 242312330.
It is an arithmetic number, because the mean of its divisors is an integer number (2382293476332).
Almost surely, 2103231311131130 is an apocalyptic number.
103231311131130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
103231311131130 is an abundant number, since it is smaller than the sum of its proper divisors (201702253839366).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103231311131130 is a wasteful number, since it uses less digits than its factorization.
103231311131130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 515112.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 103231311131130 its reverse (31131113132301), we get a palindrome (134362424263431).
The spelling of 103231311131130 in words is "one hundred three trillion, two hundred thirty-one billion, three hundred eleven million, one hundred thirty-one thousand, one hundred thirty".
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