Base | Representation |
---|---|
bin | 10111011110001111001111… |
… | …000101101000111001010100 |
3 | 111112111222110012020222022221 |
4 | 113132033033011220321110 |
5 | 102012332202402240200 |
6 | 1003320331442232124 |
7 | 30513224210016442 |
oct | 2736171705507124 |
9 | 445458405228287 |
10 | 103233013321300 |
11 | 2a990969816a65 |
12 | b6b32bb355644 |
13 | 457aaa6726b55 |
14 | 1b6c70c507b92 |
15 | be04da8d791a |
hex | 5de3cf168e54 |
103233013321300 has 36 divisors (see below), whose sum is σ = 224163895779936. Its totient is φ = 41265876872800.
The previous prime is 103233013321253. The next prime is 103233013321349. The reversal of 103233013321300 is 3123310332301.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 341453842 + ... + 341756041.
It is an arithmetic number, because the mean of its divisors is an integer number (6226774882776).
Almost surely, 2103233013321300 is an apocalyptic number.
103233013321300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
103233013321300 is an abundant number, since it is smaller than the sum of its proper divisors (120930882458636).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103233013321300 is a wasteful number, since it uses less digits than its factorization.
103233013321300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 683211408 (or 683211401 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 103233013321300 its reverse (3123310332301), we get a palindrome (106356323653601).
The spelling of 103233013321300 in words is "one hundred three trillion, two hundred thirty-three billion, thirteen million, three hundred twenty-one thousand, three hundred".
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