Base | Representation |
---|---|
bin | 10111011110010110001111… |
… | …110010010011000011111101 |
3 | 111112112200212211022220112021 |
4 | 113132112033302103003331 |
5 | 102012443112023033432 |
6 | 1003324014435240141 |
7 | 30513611566063306 |
oct | 2736261762230375 |
9 | 445480784286467 |
10 | 103240541221117 |
11 | 2a994082053573 |
12 | b6b4860449051 |
13 | 457b706202c41 |
14 | 1b6cc241dd7ad |
15 | be07cb72b697 |
hex | 5de58fc930fd |
103240541221117 has 2 divisors, whose sum is σ = 103240541221118. Its totient is φ = 103240541221116.
The previous prime is 103240541221091. The next prime is 103240541221127. The reversal of 103240541221117 is 711122145042301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 61024672325241 + 42215868895876 = 7811829^2 + 6497374^2 .
It is a cyclic number.
It is not a de Polignac number, because 103240541221117 - 211 = 103240541219069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103240541221127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51620270610558 + 51620270610559.
It is an arithmetic number, because the mean of its divisors is an integer number (51620270610559).
Almost surely, 2103240541221117 is an apocalyptic number.
It is an amenable number.
103240541221117 is a deficient number, since it is larger than the sum of its proper divisors (1).
103240541221117 is an equidigital number, since it uses as much as digits as its factorization.
103240541221117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 34.
Adding to 103240541221117 its reverse (711122145042301), we get a palindrome (814362686263418).
The spelling of 103240541221117 in words is "one hundred three trillion, two hundred forty billion, five hundred forty-one million, two hundred twenty-one thousand, one hundred seventeen".
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