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103240541221117 is a prime number
BaseRepresentation
bin10111011110010110001111…
…110010010011000011111101
3111112112200212211022220112021
4113132112033302103003331
5102012443112023033432
61003324014435240141
730513611566063306
oct2736261762230375
9445480784286467
10103240541221117
112a994082053573
12b6b4860449051
13457b706202c41
141b6cc241dd7ad
15be07cb72b697
hex5de58fc930fd

103240541221117 has 2 divisors, whose sum is σ = 103240541221118. Its totient is φ = 103240541221116.

The previous prime is 103240541221091. The next prime is 103240541221127. The reversal of 103240541221117 is 711122145042301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61024672325241 + 42215868895876 = 7811829^2 + 6497374^2 .

It is a cyclic number.

It is not a de Polignac number, because 103240541221117 - 211 = 103240541219069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103240541221127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51620270610558 + 51620270610559.

It is an arithmetic number, because the mean of its divisors is an integer number (51620270610559).

Almost surely, 2103240541221117 is an apocalyptic number.

It is an amenable number.

103240541221117 is a deficient number, since it is larger than the sum of its proper divisors (1).

103240541221117 is an equidigital number, since it uses as much as digits as its factorization.

103240541221117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13440, while the sum is 34.

Adding to 103240541221117 its reverse (711122145042301), we get a palindrome (814362686263418).

The spelling of 103240541221117 in words is "one hundred three trillion, two hundred forty billion, five hundred forty-one million, two hundred twenty-one thousand, one hundred seventeen".