Base | Representation |
---|---|
bin | 11110000011000010011… |
… | …01101110111111000101 |
3 | 10122200212100021122211212 |
4 | 33001201031232333011 |
5 | 113403400311010232 |
6 | 2110142202541205 |
7 | 134406256622561 |
oct | 17014115567705 |
9 | 3580770248755 |
10 | 1032423141317 |
11 | 368936a47957 |
12 | 148110507805 |
13 | 7648468c769 |
14 | 37d806166a1 |
15 | 1bcc7e87eb2 |
hex | f06136efc5 |
1032423141317 has 2 divisors, whose sum is σ = 1032423141318. Its totient is φ = 1032423141316.
The previous prime is 1032423141287. The next prime is 1032423141487. The reversal of 1032423141317 is 7131413242301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1028843033761 + 3580107556 = 1014319^2 + 59834^2 .
It is an emirp because it is prime and its reverse (7131413242301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1032423141317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1032423144317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516211570658 + 516211570659.
It is an arithmetic number, because the mean of its divisors is an integer number (516211570659).
Almost surely, 21032423141317 is an apocalyptic number.
It is an amenable number.
1032423141317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1032423141317 is an equidigital number, since it uses as much as digits as its factorization.
1032423141317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 1032423141317 its reverse (7131413242301), we get a palindrome (8163836383618).
The spelling of 1032423141317 in words is "one trillion, thirty-two billion, four hundred twenty-three million, one hundred forty-one thousand, three hundred seventeen".
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