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10325541173 is a prime number
BaseRepresentation
bin10011001110111001…
…10100000100110101
3222122121022211122212
421213130310010311
5132121314304143
64424332103205
7513606436403
oct114734640465
928577284585
1010325541173
114419553a02
122002004b05
13c8728b89c
146dd4a4473
15406764918
hex267734135

10325541173 has 2 divisors, whose sum is σ = 10325541174. Its totient is φ = 10325541172.

The previous prime is 10325541077. The next prime is 10325541211. The reversal of 10325541173 is 37114552301.

10325541173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6979265764 + 3346275409 = 83542^2 + 57847^2 .

It is a cyclic number.

It is not a de Polignac number, because 10325541173 - 210 = 10325540149 is a prime.

It is a super-3 number, since 3×103255411733 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10325541973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162770586 + 5162770587.

It is an arithmetic number, because the mean of its divisors is an integer number (5162770587).

Almost surely, 210325541173 is an apocalyptic number.

It is an amenable number.

10325541173 is a deficient number, since it is larger than the sum of its proper divisors (1).

10325541173 is an equidigital number, since it uses as much as digits as its factorization.

10325541173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12600, while the sum is 32.

The spelling of 10325541173 in words is "ten billion, three hundred twenty-five million, five hundred forty-one thousand, one hundred seventy-three".