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103312120229999 is a prime number
BaseRepresentation
bin10111011111011000111010…
…001110100011000001101111
3111112210112122021212022101022
4113133120322032203001233
5102020131210234324444
61003420533254004355
730522024435445352
oct2737307216430157
9445715567768338
10103312120229999
112aa1147358a35a
12b7066b80466bb
1345853a2813a75
141b72494804299
15be25ba7919ee
hex5df63a3a306f

103312120229999 has 2 divisors, whose sum is σ = 103312120230000. Its totient is φ = 103312120229998.

The previous prime is 103312120229953. The next prime is 103312120230017. The reversal of 103312120229999 is 999922021213301.

It is a strong prime.

It is an emirp because it is prime and its reverse (999922021213301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103312120229999 - 212 = 103312120225903 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 103312120229999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103312120229699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51656060114999 + 51656060115000.

It is an arithmetic number, because the mean of its divisors is an integer number (51656060115000).

Almost surely, 2103312120229999 is an apocalyptic number.

103312120229999 is a deficient number, since it is larger than the sum of its proper divisors (1).

103312120229999 is an equidigital number, since it uses as much as digits as its factorization.

103312120229999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 944784, while the sum is 53.

The spelling of 103312120229999 in words is "one hundred three trillion, three hundred twelve billion, one hundred twenty million, two hundred twenty-nine thousand, nine hundred ninety-nine".