Base | Representation |
---|---|
bin | 10011001111101010… |
… | …11100111011101111 |
3 | 222200001110222111001 |
4 | 21213311130323233 |
5 | 132124442444413 |
6 | 4425122341131 |
7 | 514015356634 |
oct | 114765347357 |
9 | 28601428431 |
10 | 10331999983 |
11 | 4422165568 |
12 | 20041ba7a7 |
13 | c88710676 |
14 | 7002a618b |
15 | 4070dd4dd |
hex | 267d5ceef |
10331999983 has 2 divisors, whose sum is σ = 10331999984. Its totient is φ = 10331999982.
The previous prime is 10331999981. The next prime is 10332000001. The reversal of 10331999983 is 38999913301.
10331999983 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10331999983 - 21 = 10331999981 is a prime.
Together with 10331999981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10331999981) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5165999991 + 5165999992.
It is an arithmetic number, because the mean of its divisors is an integer number (5165999992).
Almost surely, 210331999983 is an apocalyptic number.
10331999983 is a deficient number, since it is larger than the sum of its proper divisors (1).
10331999983 is an equidigital number, since it uses as much as digits as its factorization.
10331999983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1417176, while the sum is 55.
It can be divided in two parts, 103319 and 99983, that added together give a palindrome (203302).
The spelling of 10331999983 in words is "ten billion, three hundred thirty-one million, nine hundred ninety-nine thousand, nine hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •