Search a number
-
+
10332013421 is a prime number
BaseRepresentation
bin10011001111101011…
…00000001101101101
3222200001111122220202
421213311200031231
5132124443412141
64425122523245
7514015444052
oct114765401555
928601448822
1010332013421
114422174674
122004206525
13c88716812
147002ab029
154070e249b
hex267d6036d

10332013421 has 2 divisors, whose sum is σ = 10332013422. Its totient is φ = 10332013420.

The previous prime is 10332013369. The next prime is 10332013423. The reversal of 10332013421 is 12431023301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10320528100 + 11485321 = 101590^2 + 3389^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10332013421 is a prime.

It is a Sophie Germain prime.

Together with 10332013423, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10332013393 and 10332013402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10332013423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5166006710 + 5166006711.

It is an arithmetic number, because the mean of its divisors is an integer number (5166006711).

Almost surely, 210332013421 is an apocalyptic number.

It is an amenable number.

10332013421 is a deficient number, since it is larger than the sum of its proper divisors (1).

10332013421 is an equidigital number, since it uses as much as digits as its factorization.

10332013421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 10332013421 its reverse (12431023301), we get a palindrome (22763036722).

The spelling of 10332013421 in words is "ten billion, three hundred thirty-two million, thirteen thousand, four hundred twenty-one".