Base | Representation |
---|---|
bin | 1001011001011101111010… |
… | …0111011010100010001011 |
3 | 1100120211121200101200211121 |
4 | 2112113132213122202023 |
5 | 2323244223043034011 |
6 | 33550550331140111 |
7 | 2114354424116245 |
oct | 226273647324213 |
9 | 40524550350747 |
10 | 10333131221131 |
11 | 3324290210104 |
12 | 11aa7688a4637 |
13 | 59c543c88c94 |
14 | 27a1aa4bd095 |
15 | 12dbc608ee71 |
hex | 965de9da88b |
10333131221131 has 2 divisors, whose sum is σ = 10333131221132. Its totient is φ = 10333131221130.
The previous prime is 10333131221111. The next prime is 10333131221167. The reversal of 10333131221131 is 13112213133301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10333131221131 - 211 = 10333131219083 is a prime.
It is a super-2 number, since 2×103331312211312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10333131221096 and 10333131221105.
It is not a weakly prime, because it can be changed into another prime (10333131221111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5166565610565 + 5166565610566.
It is an arithmetic number, because the mean of its divisors is an integer number (5166565610566).
Almost surely, 210333131221131 is an apocalyptic number.
10333131221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10333131221131 is an equidigital number, since it uses as much as digits as its factorization.
10333131221131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 10333131221131 its reverse (13112213133301), we get a palindrome (23445344354432).
The spelling of 10333131221131 in words is "ten trillion, three hundred thirty-three billion, one hundred thirty-one million, two hundred twenty-one thousand, one hundred thirty-one".
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