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103352412112 = 246459525757
BaseRepresentation
bin110000001000001001…
…0001010011111010000
3100212202210210112010021
41200100102022133100
53143131204141422
6115251320513224
710316112002515
oct1402022123720
9325683715107
10103352412112
113a916818a24
121804461b814
139991213051
1450063a130c
152a4d6e1dc7
hex181048a7d0

103352412112 has 10 divisors (see below), whose sum is σ = 200245298498. Its totient is φ = 51676206048.

The previous prime is 103352412089. The next prime is 103352412127. The reversal of 103352412112 is 211214253301.

103352412112 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 94202341776 + 9150070336 = 306924^2 + 95656^2 .

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3229762863 + ... + 3229762894.

Almost surely, 2103352412112 is an apocalyptic number.

It is an amenable number.

103352412112 is a deficient number, since it is larger than the sum of its proper divisors (96892886386).

103352412112 is an equidigital number, since it uses as much as digits as its factorization.

103352412112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6459525765 (or 6459525759 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 103352412112 its reverse (211214253301), we get a palindrome (314566665413).

The spelling of 103352412112 in words is "one hundred three billion, three hundred fifty-two million, four hundred twelve thousand, one hundred twelve".

Divisors: 1 2 4 8 16 6459525757 12919051514 25838103028 51676206056 103352412112